What number should be added to the numbers 3,7 and 13 so that they are in a continued proportion?
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Continued proportion=a:b::bc
ac=bc
Let Number added be=x
Means, (a+x):(b+x)::(b+x):(c+x)
a=3
b=7
c=13
so,
(3+x):(7+x)::(7+x):(13+x)
(3+x)×(13+x)=(7+x)×(7+x)
39+3x+13x+x²=49+7x+7x
+x²
3x+13x+x²-7x-7x-x²=49-39
16x-14x=10 (+x² and-x² will be cut as positive negative)
2x=10
x=10/2
x=5
Number added=5
Hopes it's help
Thanks
ac=bc
Let Number added be=x
Means, (a+x):(b+x)::(b+x):(c+x)
a=3
b=7
c=13
so,
(3+x):(7+x)::(7+x):(13+x)
(3+x)×(13+x)=(7+x)×(7+x)
39+3x+13x+x²=49+7x+7x
+x²
3x+13x+x²-7x-7x-x²=49-39
16x-14x=10 (+x² and-x² will be cut as positive negative)
2x=10
x=10/2
x=5
Number added=5
Hopes it's help
Thanks
pratyush4211:
it is right or wrong
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