When a certain metal was radiated with light of frequency 3.2 x 10^16 Hz, the photo electrons emitted had twice the K.E as did photoelectrons emitted when the same metal was radiated with light of frequency 20 x 10^16 Hz. calculate Vo for the metal....
Answers
Answered by
1
Answer:
Happy independence day I love you so much and I'm so sorry for the late reply I was just wondering if you have any questions please feel free to question me at any time and I will be there at any time.Now I am your girlfriend
Answered by
0
Answer:
E(Total Energy)=Eo(Minimum Energy reqd. for the electron)+K.E(kinetic Energy of Photo electron)
hv=hv0 + 1/2 mv2
6.6*10-34*(3.2 * 1016) =Eo+ K.E
2.112*10-17 =Eo+ K.E......................(1)
6.6*10-34*(2*1016) =Eo+ 2*K.E.
1.32*10-17=Eo+ 2 K.E .......................(2)
solving equation (1) and (2):
Eo=2.904*10-17 j
Explanation:
.................................................................................................
Similar questions