when the same amount of electricity is passed through solutions of silver nitrate and copper sulphate , 0.4 grams copper is deposited the amount of silver deposited is?
Answers
Answered by
1
63.5 gm copper = 2×96500C charge
0.4 gm copper = (19300/63.5)×0.4=121.57 charge
96500 C = 107.8gm Silver
121.57 C = (107.9/96500)×121.57=0.14 gm of silver
0.4 gm copper = (19300/63.5)×0.4=121.57 charge
96500 C = 107.8gm Silver
121.57 C = (107.9/96500)×121.57=0.14 gm of silver
syednajeeb:
sry the answer in the book was 1.34
Similar questions