which term of an AP 41,38,35 is the first negative term and also find the term
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We can solve it with hit and trail method.
let us consider the negative number to be -1
So by using formula = a+(n-1)d where
a = 41, d = -3
:-) 41+(n-1)-3 = -1
:-) 41+(n-1)-3 = -1
:-) 41-3n+3 = -1
:-) 44-3n= -1
:-) -3n = -45
:-) n = -45/-3
Therefore n=15, So we can say that the first negative term of the given AP is the fifteenth term which is -1.
We can verify this by replacing the value of n in the formula a+(n-1)d.
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