With the help of Einstein equation Find the mass tranfromed to energy when the speed of light is 3×10e8 and the energy released during nuclear reaction is 9×10e10
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W. k.t e=mc^2
=> m = e/(c^2)
= 9×10^10/(3×10^8)^2
=9 × 10^10/9 × 10^16
= 1/10^7
=10^(-7) g
note : the mass is very small because the energy increases by speed of light squared which is a huge number
=> m = e/(c^2)
= 9×10^10/(3×10^8)^2
=9 × 10^10/9 × 10^16
= 1/10^7
=10^(-7) g
note : the mass is very small because the energy increases by speed of light squared which is a huge number
nimzkhan08:
My answer is m= 1×10e30
how?
I may be wrong too
First according to the formula I have squared the value of c
ok
Then devide it by the given value of E
U should divide e by c squared
not the other way around
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