Question

Work done on a satellite of mass 'm' at a height 'H' by the gravitational force of attraction of earth is - *

1 point

mgH

Zero

Infinity

1/2 mv²​

Answer 1

Answer

• mgh is the required answer.

Explanation

Given:-

• Mass of satellite = m

• Height = h

To Find:-

• Work done , W

Solution:-

As we know that acceleration produce in a body due to earth's Gravitational force is called acceleration due to gravity.

Acceleration due to gravity is generally taken 9.8m/s².

Here we have to calculate the work done by Gravitational force on the satellite. The work done by the gravitational force is

• Work Done = Mass × Acceleration due to gravity × Height

Substitute the value we get

→ W = mgh

Hence,mgh is the required answer.

Answer 2

Answer:

Question :-

Work done on a satellite of mass 'm' at a height 'H' by the gravitational force of attraction of earth is - *

Answer :-

Mgh

Solution :-

As we know that Work done is the product of Mass gravity (9.8 m/s²) and Height.

Where

M denotes Mass

G denotes Gravity

H denotes Height

Therefore,

$\huge \bf \: Mgh (a)\:$