Question

write a quadratic polynomial sum of whose zeros is 3and product is 2​

Answer 1

Step-by-step explanation:

Let the two zeroes be

\alpha \: and \: \betaαandβ

\begin{gathered} \alpha + \beta = 3 \\ \alpha \beta = - 10 \\ {x}^{2} - ( \alpha + \beta)x + ( \alpha \beta ) \\ {x}^{2} + 3x - ( - 10) \\ = {x}^{2} + 3x + 10 \\ therefore \: the \: required \: polynomial \: is \: {x}^{2} + 3x + 10\end{gathered}

α+β=3

αβ=−10

x

2

−(α+β)x+(αβ)

x

2

+3x−(−10)

=x

2

+3x+10

thereforetherequiredpolynomialisx

2

+3x+10

Answer 2

Step-by-step explanation:

we know that

any quadrant polynomial is of form

k[x²+(a+b)x + ab]