Question

Write the sequence of colour bands on a carbon resistor whose value is 4752 47 10% Ω ± .

Answer 1

Dear Student,

◆ Answer -

Yellow, Grey, Yellow, Silver

● Explaination -

Given resistance can be rounded off as as -

475247 ± 10% Ω = 48×10^4 ± 10% Ω

So its colour code will be -

4 => Yellow

8 => Grey

10^4 => Yellow

±10% => Silver

Therefore, colour code of resistor will be Yellow, Grey, Yellow, Silver.

◆ Extra information -

On standard resistor, there are 4 bands.

First two band indicates digits, 3rd band indicates no of zeroes and 4th bamd indicates tolerance.

# Values of colour codes-

Black = 0

Brown = 1

Red = 2

Orange = 3

Yellow = 4

Green = 5

Blue = 6

Violet = 7

Grey = 8

White = 9

Tolerance band -

No band = ±20 %

Silver = ±10 %

Gold = ±5 %

Thanks dear...