x+2,x+4,x+9........is an ap justify your answer
Answers
Answer:
Step-by-step explanation:
here
a1=x+2
a2=x+4
a3=x+9
then, d= a2-a1 and a3-a2
here a2-a1=x+4-(x+2)=x+4-x-2=2
and a3-a2=x+9-(x+4)=x+9-x-4=5
here a2-a1 is not equal to a3-a2
so it is not an ap
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x + 2, x + 4 , x + 9 does not form AP
Solution:
Given that,
We have to check if x + 2, x + 4 , x + 9 forms a arithmetic progression or not
In arithmetic progression, the difference between a term and its previous term is constant
Given is:
x + 2, x + 4 , x + 9
Find the common difference:
d = x + 4 - x - 2 = 2
d = x + 9 - x - 4 = 5
Thus, the common difference is not constant
Therefore, x + 2, x + 4 , x + 9 does not form AP
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