Math, asked by phanindranaidu66, 1 year ago

x+2,x+4,x+9........is an ap justify your answer


phanindranaidu66: it is whole question

Answers

Answered by saiharshitha494
22

Answer:


Step-by-step explanation:

here

a1=x+2

a2=x+4

a3=x+9

then, d= a2-a1 and a3-a2

here a2-a1=x+4-(x+2)=x+4-x-2=2

and a3-a2=x+9-(x+4)=x+9-x-4=5

here a2-a1 is not equal to a3-a2

so it is not an ap

hope this may help you please mark me as a brainliest dear

         


Answered by sharonr
4

x + 2, x + 4 , x + 9 does not form AP

Solution:

Given that,

We have to check if x + 2, x + 4 , x + 9 forms a arithmetic progression or not

In arithmetic progression, the difference between a term and its previous term is constant

Given is:

x + 2, x + 4 , x + 9

Find the common difference:

d = x + 4 - x - 2 = 2

d = x + 9 - x - 4 = 5

Thus, the common difference is not constant

Therefore, x + 2, x + 4 , x + 9 does not form AP

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