Question

x=7+root40 find root x + 1/root x

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

✨✨✨ ANSWERS ✨✨✨

$x = 7 + \sqrt{48} \\ \frac{1}{x} = \frac{1}{7 + \sqrt{48} } \\ \frac{1}{x} = \frac{7 - \sqrt{48} }{1} = 7 - \sqrt{40} \\ \\( \sqrt{x} + \frac{1}{ \sqrt{x} }) {}^{2} = x + \frac{1}{x} + 2 = 7 + \sqrt{40} + \frac{7 - \sqrt{40} }{1} + 2 \\ ( \sqrt{x} + \frac{1}{ \sqrt{x} } ) = \sqrt{16} = 4$