Question

x = a sec θ, y = b tan θ find dy/dx

Answer 1

dy/dx = bCosecθ/a  .  x = a sec θ, y = b tan θ

Step-by-step explanation:

x = a sec θ,

y = b tan θ

y = b tan θ

dy/dθ  = b Sec² θ

(dtanθ/dθ   =d( Sinθ /Cosθ)/dθ     = Sinθ /(-1/Cos²θ )(-Sinθ )   +  Cosθ /Cosθ

= Sin²θ /Cos²θ  + 1  = (Sin²θ +Cos²θ) /Cos²θ = 1/Cos²θ  =Sec²θ

x = a sec θ

dx/dθ  = a  sec θ Tanθ

dsec θ/dθ   = d(1/Cosθ)/dθ  =  (-1/Cos²θ)(-Sinθ)  = Sinθ/Cos²θ

= TanθSecθ

(dy/dθ)/(dx/dθ) = b Sec² θ  / a  sec θ Tanθ

dy/dx = bsec θ /aTanθ

dy/dx = b/aSinθ

dy/dx = bCosecθ/a

और अधिक जानें :

sin(x²+5)"

brainly.in/question/15286193

sin (ax+b) फलन का अवकलन कीजिए

brainly.in/question/15286166