Question

x, y, z are three integer such that x+y+ =8, y+z=13, z+x=17, than the value of x²/y square z is:-​

Answer 1

Answer:

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Step-by-step explanation:

x+y=8, y+z=13 and z+x=17

x^2/yz=?

y+z-(x+y)=13–8

=>z-x=5

Again

z-x+z+x=5+17

=>2z=22

=>z=11

Putting z in z+x and y+z we get

11+x=17 y+11=13

x=6 and y=2

Therefore, x^2/yz = 36/11*2

x^2/yz = 18/11