X2+y2=29, xy=2, find the value of x-y
luckygirl:
is the 2x or xsquare
Answers
Answered by
9
(x-y)2 = X2+ Y2- 2XY
(x-y)2 = 29-2×2
(x-y)2= 25
(x-y) = √25
(x-y) = 5
(x-y)2 = 29-2×2
(x-y)2= 25
(x-y) = √25
(x-y) = 5
Answered by
5
Hope u like my process
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Formula to be used
=-=-=-=-=-=-=-=-=-=-=-=

_______________________
Given :-
=-=-=-=-=
=> x² + y² = 29
=> xy = 2
_______________
So,

_______________________
Hope this is ur required answer
Proud to help you
=====================
Formula to be used
=-=-=-=-=-=-=-=-=-=-=-=
_______________________
Given :-
=-=-=-=-=
=> x² + y² = 29
=> xy = 2
_______________
So,
_______________________
Hope this is ur required answer
Proud to help you
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