Y=√{(1-cosx)/(1+cosx)}, then dy/dx=?
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y =√(1-cosx)/(1+cosx)
y = √(1-cosx)(1-cosx)/(1+cosx)(1-cosx)
y = 1-cosx /sinx = cosecx - cotx
dy/dx = d cosecx/dx - dcotx/dx
= -cosecxcotx + cosec²x
Thats it!
I hope you understand the solution.
All the best!
y = √(1-cosx)(1-cosx)/(1+cosx)(1-cosx)
y = 1-cosx /sinx = cosecx - cotx
dy/dx = d cosecx/dx - dcotx/dx
= -cosecxcotx + cosec²x
Thats it!
I hope you understand the solution.
All the best!
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