Zinc and copper are melted together in the ratio 9 : 11. what is the weight of melted mixture, if 28.8kg of zinc has been consumed in it?
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Answered by
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Hi friend
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zinc : copper = 9:11
weight of zinc = 28.8Kg
Let the weight copper be x Kg.
9/11 = 28.8 Kg / xKg
( cross multiply)
9x = 28.8Kg *11
x. = 28.8 Kg * 11 /9
x = 35.2 Kg
Ans. = 35.2 Kg of copper has been consumed in it.
__________________
Hope it helps! ^_^
_____________________
zinc : copper = 9:11
weight of zinc = 28.8Kg
Let the weight copper be x Kg.
9/11 = 28.8 Kg / xKg
( cross multiply)
9x = 28.8Kg *11
x. = 28.8 Kg * 11 /9
x = 35.2 Kg
Ans. = 35.2 Kg of copper has been consumed in it.
__________________
Hope it helps! ^_^
Answered by
0
Answer:
hi
Step-by-step explanation:
For 9 kg zinc, mixture melted = (9 + 11) kg
For 28.8 kg zinc , mixture melted = (20/9*28.8)
=64kg
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