Question

A bag contains 8 red balls and 5 white balls. two successive draws of 3 balls are made without replacement. find the probability that the first drawing will give 3 white balls and the second 3 red balls

Answer 1

first total 13 balls
P (White ball)=13-(8+2)/2= 1.5
second
P (red ball)=13-(5+5)/2=1.5

Answer 2

Answer:

Probability = 0.013

Step-by-step explanation:

In the question,

Number of Red balls = 8

Number of White balls = 5

Two Draws are made without replacement.

So,

Probability is given by,

$Probability=\frac{Favourable\ outcomes}{Total\ possibilities}$

So,

Probability of getting 3 white balls in the first draw is given by,

$Probability=(\frac{5}{13})\times (\frac{5}{13})\times (\frac{5}{13})=(\frac{5}{13})^{3}$

Now,

Probability of getting 3 red balls in the second draw is given by,

$Probability=(\frac{8}{13})\times (\frac{8}{13})\times (\frac{8}{13})=(\frac{8}{13})^{3}$

So,

The overall probability is given by,

$Probability=(\frac{5}{13})^{3}\times (\frac{8}{13})^{3}=\frac{64000}{4826809}\\Probability=0.013$