Physics, asked by nandanashibu358, 6 months ago

A ball is thrown vertically upwards with
a speed of 30 m/s. If the acceleration due
to gravity is 10 m/s2, the distance trav-
elled by the ball during the last second
of its motion is
O A 5 m
OB 10 m
O C 15 m
OD 20 m​

Answers

Answered by beebiayesha147
0

Answer:

option c is answer

Explanation:

30÷10×3

Answered by singlamonika1980
0

Explanation:

u=30m/s

v=0

g=-10m/s²

v=u+gt

30=10t

t=3s

distance in last second

S=u+a/2(2t-1)

=30-5(6-1)

=30-25

= 5m

Pls thank my answer....

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