a body of mass 3kg is thrown vertically upwards with an initial velocity 20m/s what will be its potential energy at the end of 2s (take g equal 10m/s2
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Answered by
1
h=ut-gt^2/2
=20×2-10×2×2/2
=40-20
.•.h=20m
potential energy=mgh
=3×10×20
=600 j
=20×2-10×2×2/2
=40-20
.•.h=20m
potential energy=mgh
=3×10×20
=600 j
Answered by
0
h=s=? (HERE * IMPLIES MULTIPLICATION)
u=20 m/s
v=0
a=10 m/s
t =2 secs
h=u t+1/2 at 2
20*2+1/2*10*[2*2]
40-1/2*10*4
40-20= 20m -height
p.e=m*g*h
= 3*10*20
= 30*20 =600 J
u=20 m/s
v=0
a=10 m/s
t =2 secs
h=u t+1/2 at 2
20*2+1/2*10*[2*2]
40-1/2*10*4
40-20= 20m -height
p.e=m*g*h
= 3*10*20
= 30*20 =600 J
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