Question

a force of 10 newton displaces a body by distance of 2 m at an angle 60 degree to its own direction. Find the amount of work done

Answer 1

W = F. s

So, W = F*s*(cos x)

So, here,
W = (10)*2*(cos 60)
= 20*(0.5)
= 10....

Cos 60 is 0.5

Answer 2

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Force, F = 10 N

Angle with horizontal, θ = 60o

Displacement in horizontal direction, S = 2 m

Component of force along horizontal direction is = F cosθ = (10)(cos60) = 5 N

So, work done is, W = (5)(2) = 10 J

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