Question

a particle is moving in xy-plane in a cirvular path with centre at origin. If at an instant the position of particle is given by 1/root2 ( icap+jcap) the velocity of particle is along

Answer 1

Answer:

Hi bro what's up you need to only focus on it

since velocity is always perpendicular to the radius of the circle in which a particle is moving (In circular motion). 

I think that we should use dot product( scalar product) as it is always zero for two mutually perpendicular vectors (i.e. its position vector and velocity vector). 

multiply 1) and 3) with 1/√ 2(i hat+j hat) and you will get 0. thus both 1) and 3) are perpendicular to position and hence both of them can be velocity vector. So, my answer is 4).may it help you mark it as brilliant if you likely

Read more on Brainly.in - https://brainly.in/question/2753966#readmorexplanation:

Answer 2

explanation in photo.....please see attachment