A road roller takes 950 complete revolution to move one over to level the road. Find the area of the road. If the diameter of the road roller is 168 centimeters and length is 2 meters.
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CSA of the road roller = 2πrh
Here , r = 168/2 = 84 cm
h = 2 m = 200 cm
2πrh = 2 x 22/7 x 84 x 200
= 105600 sq cm
Area of the road = 105600÷950 = 111.2 sq cm
Hope This Helps You!
Here , r = 168/2 = 84 cm
h = 2 m = 200 cm
2πrh = 2 x 22/7 x 84 x 200
= 105600 sq cm
Area of the road = 105600÷950 = 111.2 sq cm
Hope This Helps You!
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