ABCD is a Quadrilateral E,F,G
and H are the mid points of the sides AB,BC, CD and DA respectively.
Prove that EFGH is a parallelogram.
Draw a rough figure and prove.
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Construction: Join BD(enclosed figure)
Now,
In ∆ABD, E and H are the midpoints of sides AB and AD respectively.
So,
➡EH||BD
➡EH=1/2 BD-----(1)--{By Midpoint theorem}
Also, in ∆BDC, F and G are the midpoints of sides BC and CD respectively.
➡FG||BD
➡FG=1/2 BD------(2)---{Midpoint theorem}
From (1) and (2), we get
↪EH=FG
↪EH||FG
One pair of opposite side of the quadrilateral is equal and parallel, therefore EFGH is a parallelogram.
Hence proved.
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