an athlete completes one round of circular track of radius R in 30 seconds with uniform speed the ratio of the distance to displacement travelled by the athlete at the end of 45 seconds is
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Answered by
21
after 45 seconds means 30+15 that is a full rotation and an half of the rotation.
in one complete rotation the distance is 2πR
and displacement is 0.(as it reaches the same position)
in another 15 seconds ...
the distance covered = πR ( half of actual distance)
displacement in 15 seconds = 2R(as it covers half , the displacement is the diameter)
total distance = 2πR+πR
=>3πR
total displacement=0+2R
=>2R
ratio of distance and displacement = 3πR:2R
=>3π:2
if it is correct thank me. if it is not correct comment.
in one complete rotation the distance is 2πR
and displacement is 0.(as it reaches the same position)
in another 15 seconds ...
the distance covered = πR ( half of actual distance)
displacement in 15 seconds = 2R(as it covers half , the displacement is the diameter)
total distance = 2πR+πR
=>3πR
total displacement=0+2R
=>2R
ratio of distance and displacement = 3πR:2R
=>3π:2
if it is correct thank me. if it is not correct comment.
Answered by
6
Answer: 3π:2
Explanation:
Given that the athlete completes one round in 30s
so he completes 2πr distance in 30s
so in 45s he will cover
45×(2πr/30) = 3πr
so distance is 3πr
Now displacement
the distance travelled is 3πr and the circumference is 2πr
So clearly the athlete has completed one and half round
so displacement is the diameter, i.e. 2r
now ratio is 3πr : 2r
which gives 3π:2
Hope that's helpful
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