Anyone Know This???
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which one
both??
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4) Area of rhombus = 1/2*product of two diagonals
Area = 1/2*20*24
= 240 m^2.
5) Varun did his rationalisation as follows
1/root7 - root 3
= 1/root7 - root3 * root 7 + root3 / root 7-root 3
= root 7 + root 3 / 7 - 3
= root 7 + root 3 / 4.
Area = 1/2*20*24
= 240 m^2.
5) Varun did his rationalisation as follows
1/root7 - root 3
= 1/root7 - root3 * root 7 + root3 / root 7-root 3
= root 7 + root 3 / 7 - 3
= root 7 + root 3 / 4.
it's given the side of the rhombus is 20cm not the Length of another diagonal
Omg yaa sorry
mention not :)
its wrong
ans is 384 c.m square
Yep
u can edit it na
Now you've given the answer n.a.
So it's okk now
ok ok
Answered by
2
hiii!!!
I can only solve the first one.
1. given side of the rhombus is 20cm and one of the diagonal's length is 24cm.
by Pythagoras thereom we will find the half Length of the another diagonal.
let the hypontuse be the side of the rhombus.
base = 24/2
= 12cm
=> a² + b² = c²
=> 12² + b² = 20²
=> 144 + b² = 400
=> b² = 400 - 144
=> b² = 256
=> b = √256
=> b = 16cm
therefore the length of the diagonal = 16 × 2
= 32cm
now,
area of the rhombus = 1/2×d1×d2
= 1/2×24×32
= 12×32
= 384cm²
hope this helps..!
sorry, I don't know to solve the 2nd question.
I can only solve the first one.
1. given side of the rhombus is 20cm and one of the diagonal's length is 24cm.
by Pythagoras thereom we will find the half Length of the another diagonal.
let the hypontuse be the side of the rhombus.
base = 24/2
= 12cm
=> a² + b² = c²
=> 12² + b² = 20²
=> 144 + b² = 400
=> b² = 400 - 144
=> b² = 256
=> b = √256
=> b = 16cm
therefore the length of the diagonal = 16 × 2
= 32cm
now,
area of the rhombus = 1/2×d1×d2
= 1/2×24×32
= 12×32
= 384cm²
hope this helps..!
sorry, I don't know to solve the 2nd question.
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