Are the two triangles formed by drawing perpendicular from vertex to base in an equilateral triangle congruent. Explain with figure.
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Yes, the two triangles formed by drawing perpendicular from vertex to base in an equilateral triangle congruent.
In ΔABD and ΔACD
∠1 = ∠2----------------(ABC is an equilateral Δ which means all the ∠ are equal)
AB = AC----------------(ABC is an equilateral Δ)
∠3 = ∠4----------------(In an equilateral Δ, the ⊥ is also the ∠ bisector)
∴ ΔABD≅ΔACD----------------(SAS congruence)
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