Question

Calculate the entropy change when 1 mole of ethanol is evaporated at 351 K. The molar heat of vaporisation of ethanol is 39.84 kJ mol^-1

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Answer 1

Answer:

Given,

∆Hvapour = 39840 J mol^-1

∆Hvapour = ∆Hvapour/ Tb

Tb = 351 K

∆Hvapour = 39840 / 351

∆Hvapour = 113.5 J k^-1 mol^-1

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Answer 2

Answer:

∆Hvap = 39840 J mol-1

∆Hv = ∆Hvap / Tb

Tb = 351 K

∆Hv = 39840 / 351

∆Hv = 113.5 J k-1 mol-1

Explanation:

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