Question

Calculate the number of C, N, H, and O atoms in 0.6 * 10^4 gram urea.

Answer 1

Answer:

urea formula is NH2CONH2 ( molecular mass :- 60 )

In this compound c is 1 , n is 2 , h is 4

total given mass of of urea is 6000

we know that :

mole = given mass / molecular mass

mole = 6000 / 60

= 100

we have 100 mole of urea

$we \: have \: 100 \: mole \: of \: urea \:$

$number \: of \: atom \: = mole \times avogadro \: number$

value of avogadro no is 6.022×10^23

in one mole of urea have 1 c , then 100 mole of urea have 100 c mole . Then total no. of c atom is 6.022 × 10^25

in one mole of urea have 2n , then 100 mole of urea have 200 n mole. Then total no. of n atom is 1.2044 ×10^26

in one mole of urea have 1 o , then 100 mole of urea have 100 o mole . Then total no. of o atom is 6.022 × 10^25.

in one mole of urea have 4 h , then 100 mole of urea have 400 h mole .Then the no. of o atom is 2.4088 ×10^26

i hope that it hepls u my dear frnd