Question

Consider the reactions :- [2017]
X □(→┴Cu)A□(→┴(Ag(NH₃)₂]⁺) Silver mirror
(C₂H₆O) | - OH∆ observed
| - OH∆
-------------→ Y


NH₂ - NH - C - NH₂
Z
Identify A, X, Y and Z
(a) A-Methoxymethane, X-Ethanol, Y-Ethanoic acid, ZSemicarbazide.
(b) A - Ethanal, X-Ethanol, Y - But - 2-enal,
Z-Semicarbazone
(c) A-Ethanol, X-Acetaldehyde, Y - Butanone,
Z-Hydrazone
(d) A-Methoxymethane, X-Ethanoic acid, Y-Acetate ion,
Z-hydrazine.

Answer 1

Consider the reactions :- [2017]

X □(→┴Cu)A□(→┴(Ag(NH₃)₂]⁺) Silver mirror

(C₂H₆O) | - OH∆ observed

| - OH∆

-------------→ Y

NH₂ - NH - C - NH₂

Z

Identify A, X, Y and Z

(a) A-Methoxymethane, X-Ethanol, Y-Ethanoic acid, ZSemicarbazide.

(b) A - Ethanal, X-Ethanol, Y - But - 2-enal,

Z-Semicarbazone

(c) A-Ethanol, X-Acetaldehyde, Y - Butanone,

Z-Hydrazone

(d) A-Methoxymethane, X-Ethanoic acid, Y-Acetate ion,

Z-hydrazine.

Answer 2

A - Ethanal, X-Ethanol, Y - But - 2-enal,

Z-Semicarbazone.

Explanation:

• The formula of X is C3H6O.

• So it can be an alcohol or an ether.

• Now when its reacted with copper and heated it forms A which gives silver mirror test positive.

• So A is an aldehyde.

• So X must be alcohol which will react in presence of copper to produce aldehyde.

• So X is ethanol and A is ethanal.

• Now Aldehydes have alpha hydrogen.

• These aldehyde in presence of dilute base undergo condensation.

• They perform aldol condensation.

• Ethanal will condense to form But 2 enal.

• This is because the hydroxide group will pull one alpha hydrogen and go out as water, producing a double bond.

• Now with the semicarbazide, ethanal will react to form semicarbazide.

For more information about silver mirror test,

https://brainly.in/question/3442366

Silver mirror test is given by

Acetone

Ethanal

Acetic Acid

Ethanol

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which organic acid gives silver mirror test​ - Brainly.in