Math, asked by Tankion9744, 10 months ago

फलन f(x) = x^{2} + 2x – 8, x∈[-4,2] के लिए रोले के प्रमेय को सत्यापित कीजिए।

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Answered by kiran0003
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Answer:

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Answered by amitnrw
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रोले के प्रमेय को सत्यापित  किया गया f(x) = x² + 2x - 8    x∈[-4,2]

Step-by-step explanation:

f(x) = x² + 2x - 8    x∈[-4,2]

f(-4) = (-4)² + 2(-4) - 8  = 16 - 8 - 8 =0

f(2) = 2² + 2*2 - 8 = 4 + 4 - 8 = 0

f(-4) =  f(2)

फलन f(x) = x² + 2x - 8   x ∈ R पर संतत है

f'(x) = 2x + 2

फलन f'(x) = 2x + 2  x ∈ R पर संतत है

f'(c) = 2c + 2

f'(c) =( f(2)  - f(-4) )/(2 - (-4)  = (0- 0)/6

=> f'(c) = 0

=> 2c + 2 =0

=> c = - 1

- 1 ∈[-4,2]

रोले के प्रमेय को सत्यापित  किया गया

दर्शाइए कि f(x) =| cos x| द्वारा परिभाषित फलन एक संतत फलन है।

https://brainly.in/question/15286188

x = 3 पर फलन f(x) = 2x^{2} – 1 के सातत्य की जाँच कीजिए।

https://brainly.in/question/15285688

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