find the 10th term of an A.P. -1.0,-1.5,-2.0.
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a = -1.0
d = a2-a1 = -1.5-(-1.0) = -1.5+1.0 = -0.5
n = 10
an = a + (n-1)d
a10 = -1.0 + (10-1)(-0.5)
a10 = -1.0 + 9*(-0.5)
a10 = -1.0 + (-4.5)
a10 = -5.5
so, 10 term of this A.P. will be -5.5
hope this helps you...:)
d = a2-a1 = -1.5-(-1.0) = -1.5+1.0 = -0.5
n = 10
an = a + (n-1)d
a10 = -1.0 + (10-1)(-0.5)
a10 = -1.0 + 9*(-0.5)
a10 = -1.0 + (-4.5)
a10 = -5.5
so, 10 term of this A.P. will be -5.5
hope this helps you...:)
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