Math, asked by Sakchi21, 1 year ago

Find the HCF of 188 ,235, 282


Sakchi21: Please show the solving

Answers

Answered by Panzer786
17
Heya !!



Prime factorisation of 188 = 2 × 2 × 47

Prime factorisation of 235 = 5 × 47



And,


Prime factorisation of 282 = 2 × 3 × 47




HCF of 188 , 235 and 282 = 47.




Hope it will help you :-)

Sakchi21: Thank u so much for answering
Answered by flower161
9
hi mate@☺☺☺☺☺


1. Decompose all numbers into prime factors

188|2
94. |2
47. |47


235 |5
47. |47
1

 282|2
141. |3
47. |47
1

2. Write all numbers as the product of its prime factors

Prime factors of 188=22 . 47Prime factors of 235=5 . 47Prime factors of 282=2 . 3 . 47

3. Choose the common and uncommon prime factors with the greatest exponent

Common prime factors: 47

Common prime factors with the greatest exponent: 471

Uncommon prime factors: 2 , 5 , 3

Uncommon prime factors with the greatest exponent: 22, 51, 31

4. Calculate the Least Common Multiple or LCM

Remember, to find the LCM of several numbers you must multiply the common and uncommon prime factors with the greatest exponent of those numbers.

LCM = 471. 22. 51. 31 = 2820


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