Find the HCF of 188 ,235, 282
Sakchi21:
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Answered by
17
Heya !!
Prime factorisation of 188 = 2 × 2 × 47
Prime factorisation of 235 = 5 × 47
And,
Prime factorisation of 282 = 2 × 3 × 47
HCF of 188 , 235 and 282 = 47.
Hope it will help you :-)
Prime factorisation of 188 = 2 × 2 × 47
Prime factorisation of 235 = 5 × 47
And,
Prime factorisation of 282 = 2 × 3 × 47
HCF of 188 , 235 and 282 = 47.
Hope it will help you :-)
Answered by
9
hi mate@☺☺☺☺☺
1. Decompose all numbers into prime factors
188|2
94. |2
47. |47
1
235 |5
47. |47
1
282|2
141. |3
47. |47
1
2. Write all numbers as the product of its prime factors
Prime factors of 188=22 . 47Prime factors of 235=5 . 47Prime factors of 282=2 . 3 . 47
3. Choose the common and uncommon prime factors with the greatest exponent
Common prime factors: 47
Common prime factors with the greatest exponent: 471
Uncommon prime factors: 2 , 5 , 3
Uncommon prime factors with the greatest exponent: 22, 51, 31
4. Calculate the Least Common Multiple or LCM
Remember, to find the LCM of several numbers you must multiply the common and uncommon prime factors with the greatest exponent of those numbers.
LCM = 471. 22. 51. 31 = 2820
1. Decompose all numbers into prime factors
188|2
94. |2
47. |47
1
235 |5
47. |47
1
282|2
141. |3
47. |47
1
2. Write all numbers as the product of its prime factors
Prime factors of 188=22 . 47Prime factors of 235=5 . 47Prime factors of 282=2 . 3 . 47
3. Choose the common and uncommon prime factors with the greatest exponent
Common prime factors: 47
Common prime factors with the greatest exponent: 471
Uncommon prime factors: 2 , 5 , 3
Uncommon prime factors with the greatest exponent: 22, 51, 31
4. Calculate the Least Common Multiple or LCM
Remember, to find the LCM of several numbers you must multiply the common and uncommon prime factors with the greatest exponent of those numbers.
LCM = 471. 22. 51. 31 = 2820
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