Find the point on y axis equidistant from (-5,2) and (9,-2)
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(-5,2)____________________________(9,-2)
Let us consider the given points are A(-5,2) B(9,-2) & the point on y - axis be (0,y)
By using Distance Formula:
By using Distance Formula:√(x2 - x1)² + (y2 - y1)²
Here x1 = -5 & x2 = 9
y1 = 2 & y2 = -2
Putting Values
=> √(y -2)² + (0+5)² = √(y +2)² + (0 -9)²
= (y - 2)² + 25 = (y + 2)² + 81
Squaring both sides
= y² + 4 - 4y = y² + 4y + 4 + 56
= 8y = -56
= y= -7
So the Point is (0,-7)
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