Question

find the value (s) of p,if the quadratic equation 3xsqure - p√3x+4=0 has real and equal roots

Answer 1

hole it helps you ok

Answer 2

Solution :

Compare given Quadratic

equation 3x²-p√3x+4=0 by

ax²+bx+c=0 , we get

a = 3 , b =- p√3 , c = 4

Discreminant (D ) =0

[ given real and equal roots ]

b² - 4ac = 0

=> (-p√3)² - 4×3×4 = 0

=> 3p² = 48

=> p² = 16

=> p = ±√16

=> p = ± 4

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