Question

give step by step explainatation​

Answer 1

Answer:

I = 9A

1/R'= 1/2 +1/3

= 3 +2 /6

=5/6

R'= 6/5

Req = 1 +6/5

= 5 +6/5

= 11/5

= 2.2 ohm

V = I R

V = 9 x 2.2

V = 19.8 v

When we remove resistor 2

Then resistor 1 and 3 are parallel to each other than

1/R" = 1/1 +1/3

= 3 +1 /3

=4/3

R" = 3/4

R"=0.75 ohm

V = I R

19.8 = I x 0.75

I = 19.8/0.75

I = 198/75

I =2.645..

I = 3 A (approx)