HCF of 6 , 72 and 120 by euclids division algorithm
Answers
Answered by
6
6 = 2*3
72 = 2^3 *3^2
120 = 2^3*3*5
HCF = 2*3 = 6.....
72 = 2^3 *3^2
120 = 2^3*3*5
HCF = 2*3 = 6.....
Akshata1111:
please mark as brainiest
Answered by
20
According to the given question
72=6×12+0
HCF of (72,6)is 6
Then we find the HCF of (6,120)
120=6×20+0
HCF of (6,120)is 6
Therefore HCF of (6,72,120) is 6.
72=6×12+0
HCF of (72,6)is 6
Then we find the HCF of (6,120)
120=6×20+0
HCF of (6,120)is 6
Therefore HCF of (6,72,120) is 6.
Similar questions
English,
8 months ago
Science,
8 months ago
World Languages,
1 year ago
Math,
1 year ago
CBSE BOARD XII,
1 year ago
Science,
1 year ago