Math, asked by khushia239, 11 months ago

hi guys!!
want ur help plzzz
let me know this answer fast
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Answered by pragyadas
2
hi ....

here is your answer.
5Pr = 2 6Pr-1

== 5! / (5-r)! = 2 * 6! / (6-r+1)!

== 5! / (5-r)! = 2* 6! / (7 -r)!

==5! / (5r)! = 2* 6*5! / (7-r) (6-r) (5-r)!

== 1 = 12 / (7-r) (6-r) [See I have cancelled out terms from L.H.S. AND R.H.S.]

== (7-r) (6-r) = 12

==42 - 7r -6 r + r2 = 12

==r2 - 13r + 42 -12 =0

== r2 - 13r +30 =0

==r2 -10r -3r + 30 = 0

== r( r-10) - 3( r-10)=0

== (r-10) (r-3) =0

== (r-10) = 0 or r-3 =0

== r = 10 or r = 3

So, r = 3 only because the value of r cant be higher than 5 and 6 as they are the no. out of which we have to take arrangement, so 10 is neglected.

I hope this helps you

khushiagarwal239: very nice
pragyadas: thanks @khushiagarwal239 plz marked as brainlist answer
khushiagarwal239: hey the question is asked by khushia239 sista
khushiagarwal239: by the way ur class
pragyadas: sry ...
khushiagarwal239: its okay
khushiagarwal239: ur class
khushia239: hi guys
khushia239: thx 4 ur answer
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