Question

Hola..

Que :

Sudhir's age is 5 more than three times the age of Viru. Anil's age is half the age of sudhir. If the ratio of the sum of sudhir's and viru's ages to three times Anil's age is 5 : 6, then find Viru's age.


#Content quality required

Answer 1

$\textbf{ANSWER}$


Let the age of Viru be x years.


› Then the age of Sudhir is (3x + 5) years.


› Anil's age is half the age of Sudhir.


» Anil's age is
$\frac{3x \: + \: 5}{2}$
years.


› The sum of Sudhir's and Viru's ages
= x + 3x + 5 = (4x + 5) years.


› Three times Anil's age =
$3 \frac{3x \: + \: 5}{2}$
years.


• From the given condition,

$\frac{4x \: + \: 5}{3( \frac{3x \: 5}{2}) } \: = \: \frac{5}{6}$

»
$6 \: (4x \: + \: 5) = 5 \times 3 \: ( \frac{3x + 5}{2} )$
...( Cross multiplying )


» 2 × 6 (4x + 5) = 5 × 3 (3x + 5)
...( Multiplying both the sides by 2)


» 4 (4x + 5) = 5 (3x + 5)
...( Dividing both the sides by 3)


» 16x + 20 = 15x + 25

» 16x - 15x = 25 - 20

» x = 5.


Therefore, Viru's age is 5 years.


_______________________

Answer 2

Answer: Viru present age = 10 year's

Step by step explanation:

Let Viru 's present age = x years

Sudhir's present age = (5 + 3x) years

Anil's present age = (5 + 3x)/2 years

Given that, Ratio of the sum of Sudhir's and Viru's age to three times Anil's age is 5 : 6

=> (5 + 3x + x)/3(5 + 3x)/2 = 5/6

=> 2(5 + 4x)/3(5 + 3x) = 5/6

=> 12(5 + 4x) = 15(5 + 3x)

=> 4(5 + 4x) = 5(5 + 3x)

=> 20 + 16x = 25 + 15x

=> x = 5

Age of sudhir = 3x+5

=> 3 × 5 + 5

=> 20 year's

Age of Viru:

= 3x+2/2

= 3 × 5 + 5

=> 20/2

=> 10 year's

Hence, Viru present age is 10 year's.