Question

If 2^n+1 + 2^n+1 = 320, then what is the value of 'n'?

Answer 1

Answer:

n=7

Step-by-step explanation:

Answer 2

value of n: log159/log2

Step-by-step explanation:

$\ Given \ value:\\\\2^n+1+2^n+1 =320\\\\\ Find:\\\\n=?\\\\\ Solution:\\\\2^n+1+2^n+1 =320\\\\\rightarrow 2\cdot 2^n+2 =320\\\\\rightarrow 2\cdot 2^n =320-2\\\\\rightarrow 2^n =\frac{320-2}{2}$

$\rightarrow 2^n= \frac{318}{2}\\\\\rightarrow 2^n= 159\\\\\ take \ a \log \ in \ above \ equation:\\\\\rightarrow \log 2^n= \log 159\\\\\rightarrow n \log 2= \log 159\\\\\rightarrow n = \frac{\log 159}{\log 2}$

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