if (a+b)=12,ab=32 find(a2+b2) and (a-b) 2
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Answered by
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(a-b)² = (a+b)² - 4ab
= 12² - 4(32)
= 144 - 128
(a-b)² = 16
(a+b)² = a²+b²+2ab
12² = a²+b²+2(32)
144 = a²+b²+64
a²+b² = 144 - 64
a²+b² = 80
= 12² - 4(32)
= 144 - 128
(a-b)² = 16
(a+b)² = a²+b²+2ab
12² = a²+b²+2(32)
144 = a²+b²+64
a²+b² = 144 - 64
a²+b² = 80
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