if a bike of mass 40 kg changes its velocity from 6 kilometre per hour to 90 kilometre per hour in 10 seconds and find its acceleration net force on it and change of momentum during that time
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a = v-u /t
a = 6-90/10
a= - 8.2m/s2
F=ma
F =40 X - 8.2
F = - 328 N
Change of momentum =mv - mu
p =40 X 90 - 40 X 6
p = 3600- 240
p= 3360 kg m / s
Explanation:
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