Question

If a metal crystallizes in FCC unit cell having edge length a then diameter of metal atom will be

Answer 1

The diameter of the metal atom will be $\frac{a}{\sqrt{2}}$

Explanation:

We are given:

Edge length of metal = a

We know that:

Radius of an atom, $R=\frac{d}{2}$

where,

d = diameter

To calculate the edge length, we use the relation between the radius and edge length for FCC lattice:

$a=2\sqrt{2}R$

Putting values in above equation, we get:

$a=2\sqrt{2}\times \frac{d}{2}\\\\d=\frac{a}{\sqrt{2}}$

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