In any triangle ABC prove that tan (a + b) =-tan C
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in any triangle, if A, B, C are its angles,
then A+B+C=180°
A+B=180°-C
so, tan(A+B)=tan(180°-C)
as we know that tan(180-x)=-tanx
therefore, tan(180°-C)=-tanC
hence,proved!
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