Science, asked by vaamdewilsu5jii, 1 year ago

In the reactions (a) CuO + H2 = Cu + H2O, (b) MnO2 + 4HCl = MnCl2 + 2H2O + Cl2, (c) ZnO + C = Zn + CO state (i) what is oxidised to what, (ii) what is reduced to what, (iii) What is the oxidising agent? (iv) What is the reducing agent?

Answers

Answered by theochar0553634532
0

Answer:

Explanation:

(n) the reaction

MnO2 +4HCl———->MnCl2+2H2O+Cl2.

Here MnO2 is reduced to MnCl2.

ie., the oxidation no.of Mn is decreased from +4 to -2.

HCl is oxidised to chlorine molecule.

ie.,the OXIDATION-NUMBER of chlorine is increased from -1 to 0.

So MnO2 is reduced to MnCl2.

HCl is oxidised to chlorine

Similar questions