Question

the sum of a two digit number and the no. formed by interchanging the digits is 110.if 10 is subtracted from the first no.,the new number is 4 more than 5 times the sum of the digits in the first number.Find the number. answrr fastt z..!!

Answer 1

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Answer 2

Let the number be of the form 10(x) + 1(y)
The number formed by interchanging the digits is 10(y) + 1(x)
Therefore, 10x + 1y + 10y + x = 110
Therefore, 11x + 11y = 110
Therefore, x + y = 10

Now,
(10x + 1y - 10 ) - 4 = 5( x + y )
Therefore,
10x + y - 14 = 50
10x + y = 64 and x + y = 10
Subtracting both the equations, we get
9x = 54
x = 6
Plugging the value of x in any of the above two equations and solving them will give value of y as 4.

Therefor the number is 64.