O is the centre of the circle, chord AB=16 cm, radius of circle is 10 cm.Find the distance of the chord from the centre of the circle.
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In triangle AOB
OB is the distance
AB is the leng10th of the chord =16 CM
OA is the radius 10cm
By using pythagorous theorem
OB^2=AB^2-OA^2
=16^2-10^2
256-100
156
OB= root of 156
OB is the distance
AB is the leng10th of the chord =16 CM
OA is the radius 10cm
By using pythagorous theorem
OB^2=AB^2-OA^2
=16^2-10^2
256-100
156
OB= root of 156
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