Question

please give me the answer of this question ​

Answer 1

Answer:

C

Step-by-step explanation:

Modify the quadratic formula (-b +- sqrt(b^2-4ac))/(2a) to look like this:

(13 +- sqrt(169-24(3m-9)))/12

Plug in the multiple choice values, and you see that only plugging in 5 will get you 6/4 and 4/6, which are reciprocals.

Answer 2

$\bold{Given:-} \begin{cases} \sf{ \alpha + \beta = \frac{ - b}{a} } \\ \sf{ \alpha \beta = \frac{c}{a} } \end{cases}$

$Let \: \: first \: \: zero \: \: be \: \: \alpha \\ \: \: and \: \:its \: \: reciprocal \: \: be \: \: \frac{1}{ \alpha }$

A/Q,

${6x}^{2} - 13x + 3m - 9.$

$\alpha \times \frac{1}{ \alpha } = \frac{c}{a} \\ \\ \cancel \alpha \times \frac{1}{ \cancel\alpha } = \frac{3m - 9}{6} \\ \\ 1 = \frac{3m - 9}{6} . \\ \\ 6 = 3m - 9 \\ \\ 15 = 3m \\ \\ m = 5.$

$\huge \boxed{m = 5}$