Pls solve this 5th question. ..I really need it's solution
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.....do favour me
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hope it helps you......................................................................................................................
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Akanksha1710:
thanks for solving my question and giving your auspicious time to it but ......I have to say dear that your answers are wrong maybe there is some mistakes in your calculations....do check them and again thank u very much ..
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Hiii friend,
(X+1) and (X-2) are the two factor of the given polynomial.
(X+1) = 0 and X -2 = 0
X = -1 and X = 2
P(X) = X³+(A+1)X² -(B-2)X-6
P(-1) = (-1)³ + (A+1) × (-1)² - (B-2) × - 1 -6
=> -1 + A +1 - (-B+2) -6
=> -1 + A + 1 + B -2 -6
=> A+B -8 = 0
=> A + B = 8.......(1)
Also X = 2
P(2) = (2)³ + (A+1) × (2)² - (B-2) × 2 -6
=> 8 + (A+1) × 4 -(2B -4) -6
=> 8 + 4A + 4 -2B +4 -6
=> 4A - 2B +10 = 0
=> 4A - 2B = -10.......(2)
From equation 1 we get,
A + B = 8
A = 8-B......(3)
Putting the value of A in equation (2)
4A - 2B = -10
4 × (8-B) -2B = -10
32 - 4B -2B = -10
32 - 6B = -10
-6B = -10-32
-6B = -42
B = -42/-6 = 7
Putting the value of B in equation (3)
A = 8-B
A = 8 -7 = 1.
Hence,
A = 1 and B = 7
HOPE IT WILL HELP YOU..... :-)
(X+1) and (X-2) are the two factor of the given polynomial.
(X+1) = 0 and X -2 = 0
X = -1 and X = 2
P(X) = X³+(A+1)X² -(B-2)X-6
P(-1) = (-1)³ + (A+1) × (-1)² - (B-2) × - 1 -6
=> -1 + A +1 - (-B+2) -6
=> -1 + A + 1 + B -2 -6
=> A+B -8 = 0
=> A + B = 8.......(1)
Also X = 2
P(2) = (2)³ + (A+1) × (2)² - (B-2) × 2 -6
=> 8 + (A+1) × 4 -(2B -4) -6
=> 8 + 4A + 4 -2B +4 -6
=> 4A - 2B +10 = 0
=> 4A - 2B = -10.......(2)
From equation 1 we get,
A + B = 8
A = 8-B......(3)
Putting the value of A in equation (2)
4A - 2B = -10
4 × (8-B) -2B = -10
32 - 4B -2B = -10
32 - 6B = -10
-6B = -10-32
-6B = -42
B = -42/-6 = 7
Putting the value of B in equation (3)
A = 8-B
A = 8 -7 = 1.
Hence,
A = 1 and B = 7
HOPE IT WILL HELP YOU..... :-)
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