Math, asked by hemuabhi25, 11 months ago

Plzzz answer this question ASAP ....for a 7th grader.....plzzz.thanxs.....

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Answered by renuagrawal393
5

Answer:

 \frac{ {4}^{n - 2} \times  {2}^{n - 5} \times 6 \times  {2}^{n + 3}   }{3 \times  {6}^{2} }  =  \frac{2}{9}  \\   \frac{ { ({2}^{2} )}^{n - 5}  \times {2}^{n - 5} \times 6 \times  {2}^{n + 3}}{3 \times  {6}^{2} }  =  \frac{2}{9}  \\  \frac{ {2}^{2n - 10} \times  {2}^{n - 5}  \times  {2}^{n + 3}  }{3 \times 6}  =  \frac{2}{9}  \\  \frac{ {2}^{2n - 10 + n - 5 + n + 3} }{18}  =  \frac{2}{9}  \\   {2}^{2n -  12 + 2n}  = 4 \\  {2}^{4n - 12}  =  {2}^{2}  \\ comparing \: both \: side \\ 4n - 12 = 2 \\ 4n = 14 \\ n =  \frac{7}{2}  \\ hope \: it \: helps \: u....

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