prove that : 1/1-sinA+ 1/1+sinA=2sec²A
Answers
Answered by
9
HEY MATE HERE IS YOUR ANSWER
____________________
1/1-sinA + 1/1+sinA = 2sec^2A
1+sinA + 1 -sinA
= ---------------------- = 2sec^2A
(1-sin2A)
2
= ------------ = 2 sec^2A
cos^2A
= 2sec^2A = 2sec^2A
____________________
1/1-sinA + 1/1+sinA = 2sec^2A
1+sinA + 1 -sinA
= ---------------------- = 2sec^2A
(1-sin2A)
2
= ------------ = 2 sec^2A
cos^2A
= 2sec^2A = 2sec^2A
Answered by
3
Hi , there!!!
1 / 1 - sinA + 1 /1+ sinA = 2sec² A
1 × 1 -sinA / 1 + sinA / 1 + sinA + 1 × 1 - sinA / 1 +sinA × 1 -sinA
=> 1- SinA / Cos² A + 1 - sinA / cos²A
=> 2 / cos²A
=> 2 sec²A proved
formula used = sin²A + Cos²A = 1
hope it helps you!!!
thanks !!!
Ranjan kumar
1 / 1 - sinA + 1 /1+ sinA = 2sec² A
1 × 1 -sinA / 1 + sinA / 1 + sinA + 1 × 1 - sinA / 1 +sinA × 1 -sinA
=> 1- SinA / Cos² A + 1 - sinA / cos²A
=> 2 / cos²A
=> 2 sec²A proved
formula used = sin²A + Cos²A = 1
hope it helps you!!!
thanks !!!
Ranjan kumar
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