prove that 1/x+1/z =1/y
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Given that AA1,BB1,CC1 are each perpendicular to AC.
∴ AA1 \\ BB1 \\ CC1 .
To Prove : 1 / x + 1 / y = 1 / z.
Proof :
AA1 \\ BB1
∴ ΔCBB1 ~ Δ CAA1 ( AA similarity).
∴ CB1 / AC = BB1 / AA1 = z / x ---------------(1)
Also BB1 \\ CC1 .
∴ ΔABB1 ~ Δ ACC1 . ( AA similarity).
∴ AB1 / AC = BB1 / CC1 = z / y ---------------(2)
Adding (1) and (2) we get
z / x + z / y = CB1 / AC + AB1 / AC = ( CB1 + AB1 ) / AC = AC / AC = 1 --------(3)
dividing (3) by z we get
1 / x + 1 / y = 1 / z.
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